Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{12}}}}}[/tex]
Step-by-step explanation:
hypotenuse ( h ) = x
Peendicular ( p ) = 10
base ( b ) = 22
Using the Pythagoras theorem
[tex] \boxed{ \sf{ {h}^{2} = {p}^{2} + {b}^{2} }}[/tex]
[tex] \dashrightarrow{ \sf{ {x}^{2} = {10 }^{2} + {22}^{2} }}[/tex]
[tex] \dashrightarrow{ \sf{ {x}^{2} = 100 + 44}}[/tex]
[tex] \dashrightarrow{ \sf{ {x}^{2} = 144}}[/tex]
[tex] \dashrightarrow{ \sf{ \sqrt{ {x}^{2} } = \sqrt{144}}} [/tex]
[tex] \dashrightarrow{ \sf{x = 12}}[/tex]
Hope I helped!
Best regards! :D
