Consider the following intermediate chemical equations.
2
C(s)+102(g) → CO(g)
CO(g) + 2O2(g) –> C0,00)
How will oxygen appear in the final chemical equation?
O O2(g)
as a product
O2(g)
as a reactant
O(g) as a product
20 (9) as a reactant​

Respuesta :

Answer:

O O2(g) as a product

Explanation:

it is because oxygen is a gas and it must be given off in form of combustion

Answer:

O2(g) as a product

Explanation:

took the test