Answer:
Invariant points = 0
Step-by-step explanation:
When a point (h, k) is translated by a vector [tex]\binom{x}{y}[/tex], rule to be followed,
(h, k) → [(x + h), (y + k)]
Following this rule translated vertices of the rectangle OABC by a vector [tex]\binom{1}{3}[/tex] will be,
O(0,0) → O'(1, 3)
A(3, 0) → A'[(3 + 1), (0 + 3)]
→ A'(4, 3)
B(3, 3) → B'[(3 + 1), (3 + 3)]
→ B'(4, 6)
C(3, 0) → C'[(3 + 1), (0 + 3)]
→ C'(4, 3)
Therefore, every point on the perimeter of the square will get changed.
Number of invariant points = 0
