Answer:
60 square units
Step-by-step explanation:
When given only a list of coordinates, it can sometimes be convenient to compute the area from the sum ...
[tex]A=\dfrac{1}{2}\left|\sum\limits_{k=1}^n{(y_{k+1}-y_{k-1})x_k}\right|[/tex]
where the indices of the points "wrap around". Here, we are given the points ...
(10, 6), (4, 10), (14, 16), (16, 10)
so this computation gives ...
A = (1/2)|10(10-10) +4(16-6) +14(10-10) +16(6-16)|
= (1/2)|0 +40 +0 -160| = (1/2)(120)
A = 60
The area of the trapezoid is 60 square units.
