Respuesta :
Answer:
Resistor A
Explanation:
Resistors A, B and C are connected in parallel to a battery of voltage represented by V.
Since they are in parallel, the same voltage, V, passes across the three of them.
And from Ohm's law, the voltage (V) through a resistor is the product of the current (I) flowing through it and the resistance (R) of the resistor. i.e
V = I x R
=> I = [tex]\frac{V}{R}[/tex]
Therefore, assuming the values of the resistances of resistors A, B and C are A, B and C respectively,
(i) the current, [tex]I_{A}[/tex] through A is
[tex]I_{A}[/tex] = [tex]\frac{V}{A}[/tex]
(ii) the current, [tex]I_{B}[/tex] through B is
[tex]I_{B}[/tex] = [tex]\frac{V}{B}[/tex]
(iii) the current, [tex]I_{C}[/tex] through C is
[tex]I_{C}[/tex] = [tex]\frac{V}{C}[/tex]
From the foregoing, it can be deduced that the current is inversely proportional to the resistance. Therefore, the higher the resistance, the lower the current. Consequential of this, the resistor that carries the highest current is the one with the smallest resistance, which is A
Resistor A
Given:
Resistors A, B and C are connected in parallel to a battery of voltage represented by V.
Since they are in parallel, the same voltage, V, passes across the three of them.
Ohm's law:
It states that voltage (V) through a resistor is the product of the current (I) flowing through it and the resistance (R) of the resistor. i.e.
V = I x R
⇒ I = V/R
Therefore, assuming the values of the resistances of resistors A, B and C are A, B and C respectively,
(i) the current, through A is
[tex]I_A=\frac{V}{A}[/tex]
(ii) the current, through B is
[tex]I_B=\frac{V}{B}[/tex]
(iii) the current, through C is
[tex]I_C=\frac{V}{C}[/tex]
From the Ohm's law we can say that the current is inversely proportional to the resistance.
Therefore, higher the resistance, the lower is the current.
It is given that resistance of A being the smallest, thus is will carries the highest current.
Learn more:
brainly.com/question/16014555
