Answer:
Explanation:
The resistance of a material is expressed as R = ρL/A
Volume of the original material V = Area * Length = A*L
ρ is the resistivity of the material
R is the resistance
A is the cross sectional area
L is the length of the wire.
If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.
This means V = V₂
A*L = = A₂*L₂
A*L = A₂*(2 L)
A = 2 A₂
A₂ = A/2
The new resistance of the material Rf = ρL₂/A₂
R₂ = ρ(2 L)/(A/2)
Rf = 2ρL * 2/A
Rf = 4(ρL/A)
Since R = ρL/A
R₂ = 4R
Hence, the resistance of the stretched wire will be four times that of the original wire.
If the wire is stretched to twice its original length, the new resistance would be quadrupled.
The resistance (R) of a wire is given by:
[tex]R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity[/tex]
Since the wire is stretched, the new length (L₁) is twice its original length, hence:
L₁ = 2L
An increase in length affects the area, the new area (A₁) is:
initial volume = volume after stretch
AL = A₁L₁
AL = A₁(2L)
A₁ = A/2
The resistance of the stretched wire (R₁) is:
[tex]R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R[/tex]
Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.
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