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if the current in the circuit decreases, what does that mean about the rate at which the charge(and voltage) change in a capacitor?
2. the exponent of the exponential function contains RC for the given circuit. who's is a constant. use units R and C to find units of RC. write ohms in terms of volts and amps and write farads in terms of volts and coulombs. Simplify
units of RC are__________

Respuesta :

Answer:

`1. charge Q, on the capacitor increases, while the current will decrease

2. Ï„ = t = secs

Explanation:

1. consider RC  of a circuit to be am external source

voltage across the circuit is given as

v =vâ‚€(1 - [tex]e^{\frac{t}{Ï„} }[/tex])

where v = voltage

vâ‚€ = peak voltage

t = time taken

Ï„= time constant

as the charge across the capacitor increases, current decreases

the charge across the circuit is given as

Q= Qâ‚€(1 - [tex]e^{\frac{t}{Ï„} }[/tex])

charge Q is inversely proportional to the current I

hence the charge across the circuit increases

2. Ï„ = RC

unit of time constant, Ï„,

= Ω × F

=[tex]\frac{V}{I}[/tex] ˣ [tex]\frac{C}{V}[/tex]

=[tex]\frac{C}{A}[/tex]

=[tex]\frac{C}{C/t}[/tex]

Ï„ = t = secs

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