Answer:
Step-by-step explanation:
You have the following hyperbola:
[tex]\frac{x^2}{32}-\frac{y^2}{82}=1[/tex] (1)
The general for of a hyperbola:
[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex]
To construct the graph you take into account the rectangle formed by the lines x=±a and y=±b, and the asymptotes of the diagonals of the rectangles.
Furthermore, you take into account the foci of the hyperbola, which are
(0,±a).
Then, you have the lines
x = ± √32
y = ± √82
And the foci:
(0, ± √32)
The graph is shown in the attached image.
