Answer:
Average volume of H2SO4 used = (9.90 + 10 + 10.1) / 3
= 10 cm3
(subtract the final reading by inital reading and calculate the mean).
Write the balanced equation between the reaction of H2SO4 and KOH:
H2SO4 + 2KOH ---> K2SO4 + 2H2O
no. of moles of H2SO4 used = concentration x volume (in dm3)
= 1 x 10/1000
=0.01 mol
From the equation, the mole ratio of H2SO4 : KOH = 1:2,
meaning every 1 mole of H2SO4 reacts with 2 moles of KOH.
Hence, no. of moles of KOH required = 0.01 x 2 =0.02 mol
Molarity = no. of moles / volume (in dm3)
Therefore the molarity of KOH = 0.02 / (25/1000)
= 0.8M
