Answer:
x = -7/5
Step-by-step explanation:
If we square both sides of the equation, we get:
[tex]\sqrt{x^2-3x-6}=x-1\\ (\sqrt{x^2-3x-6})^2=(x-1)^2\\x^2-3x-6=x^2-2x+1\\[/tex]
Then, solving for x, we get:
[tex]x^2-3x-6=x^2-2x+1\\-3x-6=2x+1\\-6-1=2x+3x\\-7=5x\\\frac{-7}{5}=x[/tex]
So, x is equal to -7/5
