Answer:
Step-by-step explanation:
The given system is
[tex]3x+y-5=0\\2x-y-5=0[/tex]
First, you need to graph both lines. To do so, you just need to find the interceptions with both axis.
[tex]3x+y-5=0[/tex]
For [tex]x=0 \implies y=5[/tex]
For [tex]y=0 \implies x=\frac{5}{3}[/tex]
Then, you draw both points to have the straight line.
Repeat the process for the second line. The image attached shows both lines.
Remember, the solution of a linear system of equation is the common point between lines. In this case, we can observe that the solution is (2, -1).
On the other hand, to find the area of the triangle formed, we need to use the length of its base and its height.
Now, we use the area formula for triangles
[tex]A=\frac{bh}{2}=\frac{10(2)}{2}= 10 \ u^{2}[/tex]
Therefore, the area of the triangle formed is 10 square units.
