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The slope-intercept form of the equation of a line that passes through point (–3, 8) is y =- 2 /3x +8 . What is the point-slope form of the equation for this line? y – 3 = –2/3 (x + 8) y + 3 = -2/3 (x - 8) y + 8 = - 2/3 (x - 3) y - 8 = -2/3 (x + 3 )

Respuesta :

Answer:

y - 8 = - [tex]\frac{2}{3}[/tex](x + 3)

Step-by-step explanation:

y = - [tex]\frac{2}{3}[/tex] x + 8 ← is in slope- intercept form with slope m = - [tex]\frac{2}{3}[/tex]

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - [tex]\frac{2}{3}[/tex] and (a, b) = (- 3, 8), thus

y - 8 = - [tex]\frac{2}{3}[/tex] (x - (- 3)), that is

y - 8 = - [tex]\frac{2}{3}[/tex] (x + 3)

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