Answer:
nth term of geometric sequence = a(n) = [tex](3/4)(4/3)^{n-1}[/tex]
Step-by-step explanation:
nth term of geometric sequence = a(n)
nth term of geometric sequence = a(n) = [tex]ar^{n-1}[/tex]
Where,
a = first term
r = common ratio
n = number of term
So,
GP: 3/4, 1, 4/3, 16/9
a = 3/4
r = 1 / [3/4] = 4/3
n = n
nth term of geometric sequence = a(n) = [tex]ar^{n-1}[/tex]
nth term of geometric sequence = a(n) = [tex](3/4)(4/3)^{n-1}[/tex]
