Answer:
[tex]\huge\boxed{x=\dfrac{52}{7}=7\dfrac{3}{7}}[/tex]
Step-by-step explanation:
[tex]\dfrac{x}{4}+\dfrac{3}{5}=\dfrac{3x}{5}-2\qquad\text{multiply both sides by}\ LCD=20\\\\20\cdot\dfrac{x}{4}+20\cdot\dfrac{3}{5}=20\cdot\dfrac{3x}{5}-20\cdot2\\\\5\cdot x+4\cdot3=4\cdot3x-40\\\\5x+12=12x-40\qquad\text{subtract 12 from both sides}\\\\5x+12-12=12x-40-12\\\\5x=12x-52\qquad\text{subtract}\ 12x\ \text{from both sides}\\\\5x-12x=12x-12x-52\\\\-7x=-52\qquad\text{divide botgh sides by (-7)}\\\\\dfrac{-7x}{-7}=\dfrac{-52}{-7}\\\\x=\dfrac{52}{7}[/tex]
