Answer:
3 grams will be left after 6 half-lives
Step-by-step explanation:
Half-live:
Time it takes for the substance to be reduced by hall.
After n half lives:
The amount remaing is:
[tex]A(n) = A(0)(0.5)^{n}[/tex]
In which A(0) is the initial amount and n is the number of half-lives.
Starting with 210 grams of a radioactive isotope, how much will be left after 6 half-lives?
This is A(6) when A(0) = 210. So
[tex]A(n) = A(0)(0.5)^{n}[/tex]
[tex]A(6) = 210(0.5)^{6} = 3.3[/tex]
Rounding to the nearest gram
3 grams will be left after 6 half-lives
