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What is the decibel level of the sound of a ticking clock with intensity 10−9 watts per square inch? Use a logarithmic model to solve.

Respuesta :

Answer:

β = (-0.19 dB).

Step-by-step explanation:

The formula which is used to calculate the decibel level of a sound is given by :

[tex]\beta=10\log (\dfrac{I}{I_o})[/tex]

I is intensity of the sound of a ticking clock

[tex]I_o=10^{-12}\[/tex] watts per square meter

Since, [tex]1\ \text{inch}^2=\dfrac{1}{1550}\ \text{m}^2[/tex]

The intensity of a monster truck is converted into per square meter as follows:  

[tex]10^{-9}\ {W/in^2}= \dfrac{10^{-9}}{1550}\ W/m^2\\\\10^{-9}\ {W/in^2}=6.45\times 10^{-13}\ W/m^2[/tex]

So, Decibal level is :

[tex]\beta=10\log (\dfrac{6.45\times 10^{-13}}{10^{-12}})\\\\\beta =-0.19\ dB[/tex]

So, the decibel level of the sound of a ticking clock is (-0.19 dB).

Answer:

30dB

Step-by-step explanation: