Answer:
[tex]\large \boxed{\sf \ \ 2 \ \ }[/tex]
Step-by-step explanation:
Hello,
The mean of five numbers is 8 so we can write
[tex]\dfrac{x_1+x_2+x_3+x_4+x_5}{5}=8[/tex]
When another number is added the mean is 7, let s note x the another number we can write
[tex]\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7[/tex]
From the first equation we can say
[tex]x_1+x_2+x_3+x_4+x_5=8*5=40[/tex]
So the second equation becomes
[tex]\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7\\\\<=> \dfrac{40+x}{6}=7\\\\<=>40 + x = 6*7=42\\\\<=> x = 42-40 = 2\\[/tex]
The solution is then 2
Hope this helps
