A soap bubble of radius R is situated in a uniform electric field of magnitude E. The electric flux through the surface of the soap bubble is

Respuesta :

Answer:

The electric flux around the soap bubble will be

Ф = q/ε

Explanation:

The radius of the soap bubble = R

The electric field around the soap bubble = E

The electric flux = ?

The soap can be approximated to be a sphere, so we find the surface area of the sphere

For the soap bubble, the surface area will be

A =  [tex]4\pi R^{2}[/tex]

Recall that electric flux is given as

Ф = EA

substituting value of A from above, we'll have

Ф = E[tex]4\pi R^{2}[/tex]..... equ 1

Also recall that the electric field E is given as

E = q/(4πε[tex]R^{2}[/tex])

substitute the value of E into equ 1, to get

Ф = q/(4πε[tex]R^{2}[/tex]) * [tex]4\pi R^{2}[/tex]

The electric flux around the soap bubble reduces to

Ф = q/ε