Respuesta :
Answer:
number of moles of CO2 is 0.054
number of moles of CO is 0.107
number of moles of O2 remaining is 0.01 mole
mole fraction of CO is 0.63
Explanation:
Firstly, we write the equation of reaction;
3C(s) +2O2(g) → CO2(g) +2CO(g)
Now, we proceed.
From the written equation, we can deduce that
3 mol C = 2 mol O2 = 1 mol CO2 = 2 mol CO
No of mol of C reacted = 0.161 mol
limiting reactant according to the question is Carbon
a. no of mol of CO2 formed = 0.161*1/3 = 0.054 moles ( no of moles of CO2 formed is one-third of no of moles of carbon reacted. This is obtainable from their mole ratio 1:3)
b. no of mol of CO formed = 0.161*2/3 = 0.107 mol
c. no of mol of O2 remaining = 0.117 - (0.151*2/3) = 0.117-0.107 = 0.01 mole
d. mole fraction of CO = no of mol of CO/Total number of moles
= 0.107/(0.107+0.054+0.01)
= 0.625730994152 which is approximately 0.63
The number of moles of COâ‚‚, CO, and Oâ‚‚ formed is 0.054, 0.107, and 0.01 mole respectively.
And the mole fraction of CO is 0.63
Number of moles and Mole fraction:
The equation of reaction is given as the following:
3C(s) +2O₂(g) → CO₂(g) +2CO(g)
from above we can say that the number of moles required for the reaction to proceed is:
3 mol of C
2 mol of Oâ‚‚
1 mol COâ‚‚, and
2 mol CO
so the ratio is:
C:Oâ‚‚:COâ‚‚:CO = 3:2:1:2
Given that the number of mol of C produced is 0.161 mol
(i) number of mol of CO₂ formed = 0.161 × 1/3 = 0.054 moles
(ii) number of mol of CO formed = 0.161 × 2/3 = 0.107 mol
(iii) number of mol of O₂ remaining = 0.117 - (0.151 × 2/3)
                             = 0.117 - 0.107
                             = 0.01 mole
(iv) mole fraction of CO = (number of mol of CO) / (Total number of moles)
                    = 0.107 / (0.107+0.054+0.01)
                    = 0.63
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