Answer:
For this problem we have the following function given:
[tex] y= -3x^2 -29x +30[/tex]
In order to clasify the function as linear or quadratic we need to see the higher exponent for x in the equation and for this case we see that the higher exponent is 2 since we have in the first term [tex]-3x^2[/tex]. So then we can classify this equation as quadratic
Quadratic term: -3
Linear term: -29
Constant term: 30
Step-by-step explanation:
For this problem we have the following function given:
[tex] y= -3x^2 -29x +30[/tex]
In order to clasify the function as linear or quadratic we need to see the higher exponent for x in the equation and for this case we see that the higher exponent is 2 since we have in the first term [tex]-3x^2[/tex]. So then we can classify this equation as quadratic
Quadratic term: -3
Linear term: -29
Constant term: 30
