Answer:
[tex] y= cx^2 +dx +e[/tex]
We see that:
[tex] c = a, d= 2a , e= 3[/tex]
The axis of symmetry is defined by this formula:
[tex] X= - \frac{d}{2c}[/tex]
And replacing we got:
[tex] X= -\frac{2a}{2a}= -1[/tex]
Thn the axis of symmetry would be X=-1
Step-by-step explanation:
For this case we have the following function:
[tex] y = ax^2 +2ax +3[/tex]
If we compare this function with the general expression of a quadratic formula given by:
[tex] y= cx^2 +dx +e[/tex]
We see that:
[tex] c = a, d= 2a , e= 3[/tex]
The axis of symmetry is defined by this formula:
[tex] X= - \frac{d}{2c}[/tex]
And replacing we got:
[tex] X= -\frac{2a}{2a}= -1[/tex]
Thn the axis of symmetry would be X=-1
