Answer:
The answer is
[tex]$ (3x^2 - 12x + 43) + \frac{-190}{(x+4)} $[/tex]
Where
Remainder = -190
quotient = [tex]3x^2 - 12x + 43[/tex]
Step-by-step explanation:
The dividend is given as
[tex]3x^3 - 5x -18[/tex]
The divisor is given as
[tex]x + 4[/tex]
Using the long division,
Multiply [tex](x + 4)[/tex] by [tex]3x^2[/tex]
Remainder:
[tex]-12x^2 - 5x -18[/tex]
Multiply [tex](x + 4)[/tex] by [tex]-12x[/tex]
Remainder:
[tex]43x - 18[/tex]
Multiply [tex](x + 4)[/tex] by [tex]43[/tex]
Remainder:
[tex]-190[/tex]
Therefore, the answer is
[tex]$ (3x^2 - 12x + 43) + \frac{-190}{(x+4)} $[/tex]
Where
Remainder = -190
quotient = [tex]3x^2 - 12x + 43[/tex]
