Answer:
[tex] g(x) =\sqrt{x-4}[/tex]
[tex] h(x) =2x-8[/tex]
And we want to find:
[tex] g o h(x)[/tex]
Replacing we got:
[tex] go h(x)= \sqrt{2x-8 -4}= \sqrt{2x-12}[/tex]
And the restriction for this case would be:
[tex] 2x-12 \geq 0[/tex]
[tex] 2x \geq 12[/tex]
[tex] x \geq 6[/tex]
Step-by-step explanation:
Assumign that we have the following two functions:
[tex] g(x) =\sqrt{x-4}[/tex]
[tex] h(x) =2x-8[/tex]
And we want to find:
[tex] g o h(x)[/tex]
Replacing we got:
[tex] go h(x)= \sqrt{2x-8 -4}= \sqrt{2x-12}[/tex]
And the restriction for this case would be:
[tex] 2x-12 \geq 0[/tex]
[tex] 2x \geq 12[/tex]
[tex] x \geq 6[/tex]
