Answer:
[tex]L$ength of \overline{BC} \rightarrow 4$ units\\Value of y\rightarrow44^\circ\\m\angle DAB\rightarrow56^\circ\\$Value of x \rightarrow 2$ units[/tex]
Step-by-step explanation:
In parallelogram ABCD, BC=AD
Given:
BC=(6-x) units
AD =(x+2) units
Therefore:
6-x=x+2
x+x=6-2
2x=4
x=2
BC=(6-x) units
=(6-2) units
BC=4 units
The opposite angles of a parallelogram are equal. Therefore:
[tex]m\angle BCD=m\angle BAD\\12^\circ+y^\circ=100^\circ-y^\circ\\y^\circ+y^\circ=100^\circ-12^\circ\\2y^\circ=88^\circ\\y=44^\circ[/tex]
[tex]m\angle DAB=100^\circ-y^\circ\\=100^\circ-44^\circ\\m\angle DAB=56^\circ[/tex]
Therefore, the match is:
[tex]L$ength of \overline{BC} \rightarrow 4$ units\\Value of y\rightarrow44^\circ\\m\angle DAB\rightarrow56^\circ\\$Value of x \rightarrow 2$ units[/tex]
