contestada

Box A contains 5 dark chocolates and
10 milk chocolates. Box B contains 12
dark chocolates and 12 milk chocolates.
Craig picks a box at random and then
takes out one chocolate at random.
If he chooses box A, what is the probability
he chooses a milk chocolate?
% (1 d.p.)​

Respuesta :

mrseercalf

Answer:

[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

The probability of picking box A;

P(A) = 1/2

Box A has 5 dark chocolates and 10 milk chocolates.

The probability of picking a milk chocolate from box A;

P(milk in A) = [tex]\frac{10}{15}[/tex] = [tex]\frac{2}{3}[/tex]

P(A) and P(milk in A) = [tex]\frac{1}{2}[/tex] × [tex]\frac{2}{3}[/tex] = [tex]\frac{1}{3}[/tex]
Answer=2/3 or 66.6%
Explanation:
Total number of milk chocolate in Box A = 10
Total number of dark chocolate in Box A = 5
Total number of chocolates = 15
So probability of choosing Milk chocolate =
10/15*100
=> 2/3*100
=66.66%
Hope this helps you
Please mark this as the brainliest


Otras preguntas