Answer:
a. u = 19
b. t = 6
c. a = 2
Step-by-step explanation:
a. Given,
v = 34 , a = 5 , t = 3
[tex]v = u + at[/tex]
plugging the values:
[tex]34 = u + 5 \times 3[/tex]
Calculate the product
[tex]34 = u + 15[/tex]
Move 'u' to L.H.S and change its sign
[tex] - u + 34 = 15[/tex]
Move constant to RHS and change its sign
[tex] - u = 15 - 34[/tex]
Calculate
[tex] - u = - 19[/tex]
The difference sign (-) will be cancelled in both sides:
[tex]u = 19[/tex]
b. Given,
v = 50 , u = 20 , a = 5
[tex]v = u + at[/tex]
plugging the values
[tex]50 = 20 + 5 \times t[/tex]
[tex]50 = 20 + 5t[/tex]
Move 5t to L.H.S and change its sign.
Similarly, Move 50 to R.H.S and change its sign
[tex] - 5t = 20 - 50[/tex]
Calculate
[tex] - 5t = - 30[/tex]
The difference sign (-) will be cancelled in both sides
[tex]5t = 30[/tex]
Divide both sides of the equation by 5
[tex] \frac{5t}{5} = \frac{30}{5} [/tex]
Calculate
[tex]t = 6[/tex]
c. Given,
v = 22 , u = 8 , t = 7
[tex]v = u + at[/tex]
plugging the values
[tex]22 = 8 + a \times 7[/tex]
[tex]22 = 8 + 7a[/tex]
Move 7a to LHS and change its sign
Similarly, Move constant to R.H.S and change its sign
[tex] - 7a = 8 - 22[/tex]
Calculate
[tex] - 7a = - 14[/tex]
The difference sign (-) will be cancelled in both sides
[tex]7a = 14[/tex]
Divide both sides of the equation by 7
[tex] \frac{7a}{7} = \frac{14}{7} [/tex]
Calculate
[tex]a = 2[/tex]
Hope this helps...
Good luck on your assignment..
