Answer:
It is an imaginary root.
Step-by-step explanation:
When we rearrange the formula, we get 7x^2 - 5x + 1 = 0
When we put it in the quadratic formula: x = (−b±√b^2−4ac
) over 2a, we get x = 5 ± √-5^2-4(7)(1) over 2(7)
The discriminant is inside the square root. It is a -3. And because it is negative, we know that the root is an imaginary root.
