Answer:
91.29 g of Na₃PO₄ are needed to produce 1.67 moles of sodium ions.
Explanation:
The formula for sodium phosphate is Na₃PO₄
Molar mass of sodium phosphate = 164 g/mol
The dissociation of one mole of sodium phosphate produces 3 moles of sodium ions;
Na₃PO₄ ------> 3Na⁺ + PO₄³
Number of moles of Na₃PO₄ that will produce 1.67 moles of Na⁺ = 1/3 * 1.67 = 0.556 moles of Na₃PO₄
Mass of 0.556 moles of Na₃PO₄ = 0.556 moles * 164 g/mol = 91.29 g
Therefore, 91.29 g of Na₃PO₄ are needed to produce 1.67 moles of sodium ions.
