Answer:
The minimum amount of material in m^2 that will be needed to cover the whole arc will be 3.43 m^2
Step-by-step explanation:
This arc can be divide into two shape; a semi circle with a diameter of 1.9 m, and a rectangle with a width 1.9 m and a height of 1.4 m
For the semicircle, the area = [tex]\frac{\pi d^{2} }{4}[/tex] ÷ 2
where d is the diameter
==> [tex]\frac{3.142 * 1.4^{2} }{4}[/tex] ÷ 2
==> 1.539 ÷ 2 = 0.7695 m^2
For the rectangle, area = width x height
==> 1.4 x 1.9 = 2.66 m^2
Total area = 0.7695 + 2.66 = 3.43 m^2
This is the minimum amount of material that will be needed to cover the whole arc.
