Answer:
-4.30
Step-by-step explanation:
The computation of the test statistic is shown below:
Data are given in the question
Sample = 55 night students
Sample mean = 2.3
Standard deviation = 0.02
Sample = 50 day students
Sample mean = 2.35
Standard deviation = 0.08
Based on the above information, the test statistic is
[tex]z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma _1^2}{n_1} + {\sqrt{\frac{\sigma _2^2}{n_2}}}}}[/tex]
[tex]z = \frac{2.3 - 2.35}{\sqrt{\frac{(0.02)^2}{55} + {\sqrt{\frac{(0.08)^2}{50}}}}}[/tex]
= -4.30
Hence, the test statistic is -4.30
