Answer:
[tex]\huge\boxed{y=\bigg|\dfrac{1}{2}x-2\bigg|+4}[/tex]
Step-by-step explanation:
f(x) + n - translation n units up
f(x) - n - translation n units down
f(x + n) - translation n units to the left
f(x - n) - translation n units to the right
We have
[tex]y=\bigg|\dfrac{1}{2}x-2\bigg|+3\to f(x)=\bigg|\dfrac{1}{2}x-2\bigg|+3[/tex]
translation 1 unit up (f(x) + 1)
[tex]f(x)+1=\bigg(\bigg|\dfrac{1}{2}x-2\bigg|+3\bigg)+1=\bigg|\dfrac{1}{2}x-2\bigg|+3+1\\\\=\bigg|\dfrac{1}{2}x-2\bigg|+4[/tex]
