Human blood type is a trait that can be expressed with multiple alleles. A and B are both dominant to O, but neither is dominant to the other. When A and B are both present in the genotype of an individual, both alleles are expressed. If a father has Type AB blood and a mother has Type O blood, what percentage of their children are expected to have Type O blood like the mother

We know that alleles A and B are both dominant, so when they are inherited, there is a codominance of them because the two of them express. In the case of the allele O, we know that is recessive in the presence of A or B. If we put this information in a Punnet Square, we know that all their children will be AO or AB, so none of their children will be type O blood.

║ A ║ B║

O ║ AO ║BO║

luisvaschetto luisvaschetto · Answer 2 · 2021-10-26T16:03:11+02:00

The percentage of children that are expected to have Type O blood like the mother is zero (0%).

The four blood groups (A, B, AB, and O) are controlled by three alleles of a single gene: A, B, and O.

The individuals who have both A and B alleles show an AB phenotype because both alleles (A and B) are expressed, i.e., they are codominant.

Moreover, both A and B alleles are dominant over the O allele.

In consequence, individuals who have AO genotype show an A phenotype; whereas individuals who have BO genotype show a B phenotype.

In this case, all children will be a heterozygous genotype (either AO or BO) because the father has an AB genotype.

In conclusion, the percentage of children that are expected to have Type O blood like the mother is zero (0%).

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