Given: XY - tangent to circles k1(P) and k2(O) OX=16, PY=6 and OP=26 Find: XY

Answer:
XY = 24 units
Step-by-step explanation:
First of all, we need to some construction here.
Let us draw a line parallel to XY from point P towards OX, which cuts OX at point Q.
Please refer to the attached figure.
Now, Let us consider triangle OQP which is a right angled triangle, with
Hypotenuse, OP = 26 units
Height, OQ = OX - PY = 16 - 6 = 10 units
Base, PQ = ?
We can use pythagorean theorem here to find the value of PQ.
According to pythagorean theorem:
[tex]\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OP^{2} = PQ^{2} + OQ^{2}\\\Rightarrow 26^{2} = OQ^{2}+10^{2} \\\Rightarrow PQ^{2} = 26^{2}-10^{2} \\\Rightarrow PQ^{2} = 676-100 \\\Rightarrow PQ^{2} = 576\\\Rightarrow PQ= 24\ units[/tex]
Now, we can see that side PQ is equal to side XY.
[tex]\therefore[/tex] XY = 24 units is the answer.