Answer:
y=6x+31
Step-by-step explanation:
Since we are given a point and a slope, we can use the slope-intercept formula.
[tex]y-y_{1} =m(x-x_{1})[/tex]
where (x1,y1) is a point on the line and m is the slope.
The point given is (-6,-5) and the slope is 6.
x1= -6
y1= -5
m=6
[tex]y--5=6(x--6)[/tex]
A negative number subtracted from another number, or two negative signs, becomes a positive.
[tex]y+5=6(x+6)[/tex]
We want to find the equation of the line, which is y=mx+b (m is the slope and b is the y-intercept). Therefore, we must get y by itself on one side of the equation.
First, distribute the 6. Multiply each term inside the parentheses by 6.
[tex]y+5=(6*x)+(6*6)[/tex]
[tex]y+5=6x+36[/tex]
Subtract 5 from both sides, because it is being added on to y.
[tex]y+5-5=6x+36-5[/tex]
[tex]y=6x+36-5[/tex]
[tex]y=6x+31[/tex]
The equation of the line is y=6x+31
