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Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 349, x = 42

Respuesta :

abidemiokin

Answer:

0.5705

Step-by-step explanation:

Margin of error is expressed as M.E = [tex]z * \sqrt{\frac{\sigma}{n} }[/tex] where;

z is the z score at 95% confidence

[tex]\sigma[/tex] is the standard deviation

n is the sample size

Given n = 349, [tex]\sigma = 42[/tex] and z score at 95% confidence = 1.645

Substituting this values into the formula above we will have;

M.E = [tex]1.645*\sqrt{\frac{42}{349} }[/tex]

[tex]M.E = 1.645*\sqrt{0.1203} \\\\M.E = 1.645*0.3468\\\\M.E = 0.5705 (to\ four\ dp)[/tex]

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