A certain shade of blue has a frequency of 7.06×1014 Hz. What is the energy E of exactly one photon of this light? Planck's constant h=6.626×10−34 J⋅s.

Respuesta :

Answer:

Energy, [tex]E=4.67\times 10^{-19}\ J[/tex]

Explanation:

It is given that,

Frequency of blue shade is, [tex]f=7.06\times 10^{14}\ Hz[/tex]

We need to find the energy of exactly one photon of this light. The formula that is used to find the energy of photon is given by :

[tex]E=nhf[/tex]

Here, n is number of photon, n = 1

h is Planck's constant

So,

[tex]E=1\times 6.626\times 10^{-34}\times 7.06\times 10^{14}\\\\E=4.67\times 10^{-19}\ J[/tex]

So, the energy of this light is [tex]4.67\times 10^{-19}\ J[/tex].