I WILL GIVE 20 POINTS!!! This three- dimensional figure is a triangular pyramid where the base and lateral are congruent equilateral triangles and the height of each triangular face 17.32 inches The surface are of the figure is Square inches

Answer:
Hey there!
The surface area of the triangular pyramid can be expressed as: 4 times the area of one triangle.
The area of one triangle is 17.32, so the total surface area is 69.28.
Hope this helps :)
The surface area of the triangular pyramid will be equal to 692.8 square inches.
The space occupied by any two-dimensional figure in a plane is called the area. The area of the outer surface of any body is called the surface area.
Given that:-
The formula for the surface area of the pyramid is given as follows;-
SA = Base area + (1/2) [ Perimeter x Slant height ]
SA = [ (1/2) x 20 x 17.32)] + (1/2) [ 60 x 17.32 ) ]
SA= [ 173.2 + 519.6 ]
SA = 692.8 squarer inches
Therefore the surface area of the triangular pyramid will be equal to 692.8 square inches.
To know more about a surface area follow
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