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Fernando is playing hide-and-seek with Darnel and Joy. Darnel is hiding 5 meters south of Fernando, and Joy is hiding due east of Darnel. If Fernando is 8 meters from Joy, how far apart are Darnel and Joy? If necessary, round to the nearest tenth.

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abidemiokin

Answer:

6.2 metres apart

Step-by-step explanation:

Find attached a diagram for proper elucidation of the question. The resulting shape is a right angled triangle with hypotenuse FJ, and the other two sides DF and DJ respectively.

Using Pythagoras theorem to get the side DJ which is the distance between Daniel and Joy. According to the theorem, the square of the hypotenuse of a right angled triangle is equal to the sum of the other two sides.

FJ² = DF² + DJ²

From the diagram, FJ = 8 and DF = 5. Substituting this values into the theorem above to get DJ;

8² = 5²+DJ²

DJ² = 8²-5²

DJ² = 64 -25

DJ² = 39

DJ = √39

DJ = 6.2 (to the nearest tenth)

This shows that Darnel is 6.2 metres away from Joy

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