Answer:
NO.
Step-by-step explanation:
13/14 already reduced to the lowest terms;
the numerator and the denominator have no common prime factors:
13 is a prime number; 14 = 2 × 7.
25/28 already reduced to the lowest terms;
the numerator and the denominator have no common prime factors:
28=5^2 ; 282^2× 7.
The prime factorization of the denominators ; 14=2× 7; 28=2^2× 7.
Multiply all the unique prime factors, by the largest exponents: LCM (14,28)=2^2× 7=28;
Divide LCM by the denominator of each fraction:
For fraction 13/14 is, 28÷ 14=(2^2×7)÷(2x7)=2;
For fraction 25/28 is 28÷28=(2^2×7)÷(2^2×7)=1;
Expland the fractions
Multiply the numerators and the denomonators by their expanding number:
13/14=(2x13)/(2x14)=16/28;
25/28=(1x25)/(1x18)=25/28;
The fraction sorted in ascending order: 25/28<26/28
The initial fractions in ascending order:25/28<13/14
I think I did this right.
