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In the lab, Charmaine has two solutions that contain alcohol and is mixing them with each other. Solution A is 12% alcohol and Solution B is 40% alcohol. She uses 800 milliliters of Solution A. How many milliliters of Solution B does she use, if the resulting mixture is a 32% alcohol solution

Respuesta :

Answer: Charmaine wil use 2000 mL of solution B

Step-by-step explanation: Suppose that volume of solution B for the mixture is J.

Volume of solution A used is [tex]V_{A}[/tex] = 0.12*800

Volume of solution B used is [tex]V_{B}[/tex] = 0.4*J

Volume Total is V = 800 + J

0.12*800 + 0.4*J = 0.32(800 + J)

96 + 0.4J = 256 + 0.32J

0.08J = 160

J = 2000

Volume of solution B is 2000mL or 2L.