Answer:
second one
Step-by-step explanation:
The function g has this expression g(x) = ax²+c
- to have a minimum a should be positive since the parabola will open up
To find when g reaches it's minimum we must derivate it
solve g'(x) = 0
- g'(x) = 0
- 2ax = 0
- ax = 0
- x = 0
replace x with 0 in g(x)
g(0) = a(0)²+c
g(0) = c
the maximum of f(x) is 1 so for g(x) to have a grather minimum c should be greather than 1
the second statement is true
