Answer:
[tex]\frac{1}{2}[/tex] and [tex]-\frac{4}{3}[/tex]
Step-by-step explanation:
We can solve this equation using the quadratic formula, which is
[tex]\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}[/tex]
Assuming that with your equation, 6x² + 5x - 4 = 0, a is 6, b is 5, and c is -4.
We can substitute inside the equation.
[tex]\frac{{ - 5 \pm \sqrt {5^2 - 4 \cdot 6\cdot\-4} }}{{2 \cdot6}}}[/tex]
[tex]\frac{{ - 5 \pm \sqrt {25 + 96} }}{{12}}}[/tex]
[tex]\frac{{ - 5 \pm \sqrt {121} }}{{12}}}[/tex]
[tex]\frac{{ - 5 \pm 11 }}{{12}}}[/tex]
Now, we can find our two values by using subtraction/addition and division.
[tex]-5 + 11 = 6\\-5 - 11 = -16[/tex]
[tex]\frac{6}{12} =\frac{1}{2} \\-\frac{6}{12} =-\frac{4}{3}[/tex]
I hope this helped!
