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A pretzel company calculated that there is a mean of 75.4 broken pretzels in each production run with a standard deviation of 5.2. If the distribution is approximately normal, find the probability that there will be fewer than 66 broken pretzels in a run.

Respuesta :

Answer:

P [ Z < 66 ]  = 35,15 %

Step-by-step explanation:

Normal Distribution

Population mean μ₀  = 75,4

Standard deviation  σ = 5,2

Then:

P [ Z < 66 ]  =  ( 66 - 75,4 ) / 5,2

P [ Z < 66 ]  = - 9,4 / 5,2

P [ Z < 66 ]  = - 1,81

In z-table we look for the reciprocate area for that  z score and find

P [ Z < 66 ]  = 0,3515

P [ Z < 66 ]  = 35,15 %