Solve the equation
log₃2 + log₃(x-4)=1
Answer:
x = 11/2
Step-by-step explanation:
To solve this, we will follow the steps below:
log₃2 log₃(x-4)=1
applying the rules of logarithm, logₐ b + logₐ c = logₐ(bc)
our equation becomes
log₃2+ log₃(x-4)=1
log₃(2)(x-4) = 1
Also log₃3 = 1
so we will substitute 1 by log₃3 in the equation
log₃(2)(x-4) = log₃3
2(x-4) = 3
2x -8 = 3
add 8 to both-side of the equation
2x -8 + 8 = 3 + 8
2x = 11
divide both-side of the equation by 2
x = 11/2
