Answer:
[tex]\boxed{l=44 \: \mathrm{feet}, \: \: w=20 \: \mathrm{feet}}[/tex]
Step-by-step explanation:
The width (w) = l - 24
The length (l) = l
The perimeter (P) = 128
The shape is a rectangle. Use the formula for the perimeter of a rectangle.
P = 2w + 2l
Plug in the values.
128 = 2(l - 24) + 2l
Solve for l.
Expand brackets.
128 = 2l - 48 + 2l
Combine like terms
128 = 4l - 48
Add 48 on both sides.
176 = 4l
Divide both sides by 4.
44 = l
Apply formula again.
P = 2l + 2w
Solve for w.
Subtract 2w and P on both sides.
-2w = 2l - P
Divide both sides by -2.
w = -l + P/2
Plug in the values for l and P, solve for w.
w = -(44) + 128/2
w = -44 + 64
w = 20
The length is 44 feet.
The width is 20 feet.
