Answer:
The owner needs 195 meters of wire
Step-by-step explanation:
If the lot is squared shaped, then its area is given by the formula:
[tex]Area =x^2[/tex]
where x is the side of the square. Then considering the value they provide for the surface, each side must be of length:
[tex]x^2=\frac{4225}{16} \,m^2\\x=\sqrt{\frac{4225}{16}} \,\,m\\x=16.25\,\,m[/tex]
Then the perimeter around this square lot is four times that side length:
Perimeter = 4 (16.25 m) = 65 m
and since the owner wants three rows of wire, the total length of wire needed is:
3 (65 m) = 195 m
