Answer:
t = 2.01 seconds
Explanation:
It is given that,
The acceleration of the elevator is 4.55 m/s².
We need to find time taken by you to reach a speed of 11 m/s
The initial velocity of the person is equal to 0 (at rest). Let t is the time.
Using equation of kinematics as follows :
v = u +at
Acceleration = g-a and u = 0
So,
[tex]t=\dfrac{v}{g-a}\\\\t=\dfrac{11}{10-4.55}\\\\t=2.01\ s[/tex]
So, 2.01 seconds is taken to reach a speed of 11 m/s.
