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Find a polar equation r for the conic with its focus at the pole and the given eccentricity and directrix. (For convenience, the equation for the directrix is given in rectangular form.)
Conic: Parabola Eccentricity: e = 1 Directrix: y = 4

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okpalawalter8

Answer:

The  equation is  [tex]r = \frac{4 }{ 1 + cos (\theta )}[/tex]

Step-by-step explanation:

From the equation we are told that

    The  Eccentricity: e = 1

    The  Directrix is   y = 4

Generally the polar equation for e =  1  and  y  =  + c is mathematically represented as

         [tex]r = \frac{e * c }{ 1 + ecos (\theta )}[/tex]

So

         [tex]r = \frac{1 * 4 }{ 1 + 1 * cos (\theta )}[/tex]

        [tex]r = \frac{4 }{ 1 + cos (\theta )}[/tex]

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