Answer:
25 N
Explanation:
Force : This is defined as the product of mass and acceleration. The unit of force is Newton or kgm/s².
From the question,
F = ma......................... Equation 1
Where F = Force of the brake, m = mass of the break, a = acceleration.
But,
a = v/t.................. Equation 2
where v = velocity, t = time.
Substitute equation 2 into equation equation 1
F = m(v/t)................ Equation 3
Given: m = 5.0 kg, v = 10 m/s, t = 2 seconds
F = 5(10/2)
F = 25 N.
Hence the average force of the brakes on the bike is 25 N
Answer:
The average force of the brakes on the bike is 25.0 N
Explanation:
The parameters given in the question are,
Mass, m = 5.0kg
Initial velocity, u = 10 m/s
Time, t = 2 sec
Since the bike came to a complete stop, then
Final velocity, v = 0 m/s
To determine the average force of the brakes on the bike; From Newton's second law of motion, Force is given as
F = ma
Where F is the force in N (Newtons)
m is the mass in kg
and a is acceleration in m/s²
Hence, we will first determine the acceleration.
From one of the equations of kinematics for linear motion,
[tex]v = u + at[/tex]
Then, [tex]a = \frac{v - u}{t\\}[/tex]
Putting the given parameters into the above equation, we get
[tex]a = \frac{0 - 10}{2}[/tex]
[tex]a = \frac{-10}{2}\\ a = - 5[/tex]m/s²
The negative sign indicates deceleration since the bike came to a stop,
Hence, [tex]a = 5[/tex] m/s²
From,
F = ma
F = 5.0 × 5
F = 25.0 N
