Answer:
The width is 4 inches
The length is 11 inches
Step-by-step explanation:
Let the width be x inches
Let the length be (2x+3 )inches
Perimeter= 30 inches
therefore, 2(length +breadth)= perimeter
=>2(2x+3+x)=30
=>2(3x+3)=30
=>6x+6=30
=>6x=30-6
=>6x=24
=>x=24/6
=>x=4
The width is 4 inches
The length is 11 inches
To solve this question:
Doing this, we get that the length of the painting is: 11 inches.
Perimeter of a rectangle:
The perimeter of a polygon is the sum of it's sides.
For a rectangle, as the one given in the picture at the end of this answer, which is of the format of the painting, the perimeter is given by:
[tex]P = 2l + 2w[/tex]
Lisa is framing a rectangular painting the length is three more than twice the width.
This means that:
[tex]l = 3 + 2w[/tex]
Since we want to solve for the length, we write the width as a function of the length, thus:
[tex]2w = l - 3[/tex]
She uses 30 inches of framing material
This means that the perimeter is of 30 inches, that is:
[tex]2l + 2w = 30[/tex]
Since [tex]2w = l - 3[/tex]
[tex]2l + l - 3 = 30[/tex]
[tex]3l = 33[/tex]
[tex]l = \frac{33}{3}[/tex]
[tex]l = 11[/tex]
Thus, the length of the painting is of 11 inches.
A similar question is found at https://brainly.com/question/21894434
